The quantity of electricity required to deposit `1*15g` of sodium from molten `NaCl (Na = 23, Cl = 35*5)` is

Options

A. 1F
B. 0.5F
C. 0.05F
D. 1.5F

Answer

C

Explanation

Number of moles of Na-1.15/23 = 0.05 moles.
`Na^(+) + e rarr Na`
Thus, deposition of 1 mole of Na will require 1 mole of electrons which corresponds to 1 Faraday of electricity: The, deposition of 0.05 moles (1.15 g) of Na will require 0.05 moles of electrons which corresponds to 0.05 Faraday of electricity.