The reaction in presence of dry ether, `2C_(2)H_(5)Br+ 2Na rarr C_(2)H_(5) + 2NaBr` is an example of:

Options

A. The Wurtz reaction
B. Sandmeyer's reaction
C. Aldol condensation
D. Williamson's reaction

Answer

To solve the question regarding the reaction `2C_(2)H_(5)Br + 2Na → C_(2)H_(5) + 2NaBr`, we need to identify the type of reaction taking place. Let's break it down step by step.

### Step 1: Identify the Reactants
The reactants in the given reaction are:
- Ethyl bromide (C2H5Br), which is an alkyl halide.
- Sodium (Na), a metal.

### Step 2: Analyze the Reaction Conditions
The reaction occurs in the presence of dry ether. Dry ether is commonly used as a solvent in reactions involving organometallic compounds and can help facilitate the reaction between alkyl halides and metals.

### Step 3: Understand the Reaction Type
In this reaction, two moles of ethyl bromide react with two moles of sodium to produce ethane (C2H6) and sodium bromide (NaBr). This type of reaction is characterized by the coupling of alkyl halides with sodium to form hydrocarbons.

### Step 4: Identify the Reaction Mechanism
This reaction is known as the Wurtz reaction. The Wurtz reaction involves the coupling of two alkyl halides in the presence of sodium, leading to the formation of a higher alkane (in this case, ethane) and sodium halide as a byproduct.

### Step 5: Conclusion
Based on the analysis, we conclude that the given reaction is an example of the Wurtz reaction.

### Final Answer
The correct answer is that the reaction `2C_(2)H_(5)Br + 2Na → C_(2)H_(5) + 2NaBr` is an example of the Wurtz reaction.

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