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The amount of solute required to prepare...

The amount of solute required to prepare 10L of decimolar solution is:

A

0.01 mole

B

0.2 mole

C

0.05 mole

D

1 mole

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The correct Answer is:
To find the amount of solute required to prepare 10 liters of a decimolar (0.1 M) solution, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definition of Decimolar Solution**: - A decimolar solution (0.1 M) means that there are 0.1 moles of solute per liter of solution. 2. **Calculate the Total Moles of Solute Required**: - Since we need to prepare 10 liters of a decimolar solution, we can calculate the total moles of solute required using the formula: \[ \text{Total Moles} = \text{Molarity} \times \text{Volume} \] - Here, Molarity (M) = 0.1 moles/L and Volume (V) = 10 L. - Substituting the values: \[ \text{Total Moles} = 0.1 \, \text{moles/L} \times 10 \, \text{L} = 1 \, \text{mole} \] 3. **Conclusion**: - Therefore, to prepare 10 liters of a decimolar solution, you need 1 mole of solute. ### Final Answer: The amount of solute required to prepare 10 L of decimolar solution is **1 mole**. ---

To find the amount of solute required to prepare 10 liters of a decimolar (0.1 M) solution, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definition of Decimolar Solution**: - A decimolar solution (0.1 M) means that there are 0.1 moles of solute per liter of solution. 2. **Calculate the Total Moles of Solute Required**: ...
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