A chloro compound(A) on reduction with Zn-Cu and ethanol give hydrocarbon (B) with 5 carbon atoms. When(A) is dissolved dry ether and treated with sodium metal it gave 2, 2, 5, 5 tetra methyl hexane. The treatment of A as A'C (in presence of alcoholic KCN)
The compound A is:

Options

A. 1-chloro-2,2 dimethyl propane
B. 1-chloro-2,2 dimethyl propane
C. 1-chloro-2 methyl butane
D. 2-chloro-2 methyl propane

Explanation

To solve the problem, we need to identify the compound A based on the given reactions and products. Let's break down the information step by step.

### Step 1: Analyze the Reduction Reaction
The question states that a chloro compound (A) on reduction with Zn-Cu and ethanol gives a hydrocarbon (B) with 5 carbon atoms.

**Hint:** Look for a chloro compound that can yield a hydrocarbon with 5 carbon atoms upon reduction.

### Step 2: Identify the Structure of Hydrocarbon B
Since hydrocarbon B has 5 carbon atoms, we can consider possible structures. The simplest structure with 5 carbons is pentane (C5H12) or its isomers.

**Hint:** Consider the possible isomers of pentane that could be formed from a chloro compound.

### Step 3: Analyze the Reaction with Sodium Metal
The question also mentions that when compound A is treated with sodium metal in dry ether, it gives 2,2,5,5-tetramethylhexane. This suggests that compound A must have a structure that allows for coupling reactions to form this specific product.

**Hint:** The presence of multiple methyl groups in the product suggests that compound A should have branching.

### Step 4: Deduce the Structure of Compound A
From the information given, we can deduce that compound A must be a chloro compound that can lead to the formation of 2,2,5,5-tetramethylhexane upon reaction with sodium.

A suitable candidate for compound A is 1-chloro-2,2-dimethylpropane (C5H11Cl). This compound has a structure that allows for the formation of the desired hydrocarbon upon reduction and coupling.

**Hint:** Verify if the structure of 1-chloro-2,2-dimethylpropane can lead to the desired products.

### Step 5: Confirm the Structure
When 1-chloro-2,2-dimethylpropane is treated with sodium in dry ether, it can couple to form 2,2,5,5-tetramethylhexane. Additionally, the reduction with Zn-Cu in ethanol will yield a hydrocarbon with 5 carbon atoms.

**Hint:** Check the reaction pathways to ensure that the proposed structure of A leads to the correct products.

### Conclusion
Based on the analysis, the compound A is confirmed to be 1-chloro-2,2-dimethylpropane.

**Final Answer:** The compound A is 1-chloro-2,2-dimethylpropane.