Sodium methoxide on heating with bromoethane gives___________

Options

A. Methoxymethane
B. Methoxyethane
C. Ethoxyethane
D. Diethyl ether

Explanation

To solve the question about the reaction of sodium methoxide with bromoethane, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- Sodium methoxide (NaOCH3) is the first reactant. It can be represented as CH3ONa.
- Bromoethane (C2H5Br) is the second reactant, which can be written as CH3CH2Br.

2. **Understand the Reaction Type**:
- The reaction between sodium methoxide and bromoethane is a type of nucleophilic substitution reaction, specifically known as Williamson Ether Synthesis. In this reaction, the alkoxide ion (from sodium methoxide) acts as a nucleophile.

3. **Write the Reaction**:
- When sodium methoxide reacts with bromoethane, the alkoxide ion (CH3O-) attacks the carbon atom bonded to the bromine in bromoethane. This leads to the displacement of the bromine atom.
- The reaction can be represented as:
\[ CH3ONa + CH3CH2Br \rightarrow CH3OCH2CH3 + NaBr \]

4. **Identify the Products**:
- The product formed from this reaction is an ether. The ether formed is methoxyethane (also known as ethyl methyl ether), which can be represented as CH3OCH2CH3.
- Additionally, sodium bromide (NaBr) is formed as a byproduct.

5. **Final Answer**:
- Therefore, the product of the reaction between sodium methoxide and bromoethane is methoxyethane.

### Final Answer:
Methoxyethane

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