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Sulphur is more stable in the form of rh...

Sulphur is more stable in the form of rhombic sulphur which contains S_(8) rings. This on heating converts into vapour that consists of S_(2) fragments.The correct statements about these S_(8) and S_(2) molecules. (A) S -S bond length is more in S_(8) than in S_(2) . (B) S_(8) ring is diamagnetic whereas S_(2) is paramagnetic.

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is sulphur S_(2) is paramagnetic in nature and why ?

The oxidation number of sulphur in H_(2)S_(2)O_(8) is:

The oxidation state of S in H_(2)S_(2)O_(8) is

Number of S-S bond in H_(2)S_(n)O_(6) is :

Assertion :The S-S-S bond in S_(8) molecule is 105^(@) . Reason : S_(8) has V-shape.

Assertion: In vapour state sulphur is paramagnetic in nature. Reason : In vapour state sulphur exists as S_(2) molecule.

Write the formula of the compound of sulphur which is obtained when conc. HNO_(3) oxidises S_(8) .

How many S-S bonds are present in S_8 molecule ?

The oxidation state of S in S_(8) is zero.