Add the equations : `T^2cos^2theta=W^2` and `T^2sin^2theta=R^2`

If 5sin^2 theta+cos^2theta=2 then sin theta=

The solution of the equation cos^(2)theta-2cos theta=4sin theta-sin2 theta where theta in[0,pi] is

Solve the equation 2cos^(2)theta+3sin theta=0

Solve the equation 3-2cos theta-4sin theta-cos2 theta+sin2 theta=0

Find the number of solution of the equation 2(cos theta+cos2 theta)+sin2 theta(1+2cos theta)=2sin thetain theta in[0,3 pi]

The number of values of theta in the range [0,2 pi] satisfying the equation cos^(4)2 theta+2sin^(2)2 theta=17(sin theta+cos theta)^(8) is

prove that- sin^2theta/cos^2theta+cos^2theta/sin^2theta=1/ (sin^2thetacos^2theta)-2

Complete the equation. sin^(2)theta + cos^(2)theta =

The solution of the equation 1-"cos" theta = "sin" theta "sin" (theta)/(2) is

A value of theta satisfying 4cos^(2)theta sin theta-2sin^(2)theta=3sin theta is