The stress for elastic limit of a material is `3.5times10^(8)N/m^(2)` .The minimum diameter of a rod made of this material which can support 500N load without exceeding elastic limit will be

The elastic limit of brass is 379MPa . What should be the minimum diameter of a brass rod if it is to support a 400 N load without exceeding its elastic limit?

If the elastic limit of copper is 1.5xx10^(8) N//m^(2) ,determine the minimum diameter a copper wire can have under a load of 10.0 kg force , if its elastic limit is not to be exceeded.

The elastic limit of steel is 8xx10^8Nm^-2 and its Young modulus 2xx10^11Nm^-2 . Find the maximum elongation of a half meter steel wire that can be given without exceeding the elastic limit.

The elastic limit of an elavator cable is 2xx10^(9)N//m^(2) . The maximum upward acceleration that an elavator of mass 2xx10^(3)kg can have when supported by a cable whose cross sectional area is 10^(-4)m^(2) , provided the stres in cable would not exceed half to the elastic limit would be

A material beaks up under a stress of 20xx10^(5)N//m^(2) . If the density of the material is 2.5xx10^(3)kg//m^(3) , calculate the length of a wire made of this material, which on hanging may break under its own weight. (g=9.8m//s^(2))

A stress of 10^(6) N//m^(2) is required for breaking a material. If the density of the material is 3 xx 10^(3) Kg//m^(3) , then what should be the minimum length of the wire made of the same material so that it breaks by its own weight (g = 10m//s^(2))

Breaking stress for a material is 2 xx 10^8 N//m^2 . What maximum length of the wire of this material can be taken t the wire does not break by own weight? Density of material = 5 xx 10^3 kg//m^3

The breaking stress of a material is 10^(8) Nm^(-2) . Find the greatest length of a wire that could hang vertically without breaking? Density of material = 3000 kg m^(-3) .

The length of a sonometer wire is 0.75 m and density 9xx 10^(3) Kg//m^(3) . It can bear a stress of 8.1 xx 10^(8) N//m^(2) without exceeding the elastic limit . The fundamental that can be produced in the wire , is

The elastic limit of a steel cable is 3.0xx10^(8) N//m^(2) and the cross-section area is 4 cm^(2) . Find the maximum upward acceleration that can be given to a 900 kg elevator supported by the cable if the stress is not to exceed one - third of the elastic limit.