26.8g of `Na_2SO_4.nH_2O` contains 12.6 g of water.The value of `n` is

26.8 gm Na_(2)SO_(4). nH_(2)O contains 12.6 of water here the value of 'n' is ?

26.8 g of Na_2SO_4.xH_2O gave 12.6 g of water on heating. Determine the value of x in the compound using mole concept.

5 mL of 8 N HNO_(3), 4.8 mL of 5 N HCl , and a certain volume of 17 m H_(2) SO_(4) are mixed together and made upto 2 L . 30 mL of the acid mixture exactly neutralises 42.9 mL of Na_(2 CO_(3) solution containing 0.1 g of Na_(2) CO_(3). 10 H_(2) O in 10 mL of water. Calculate: The amount (in g) of the sulphate ions in the solution.

Calculate the molarity (M) of a solution of oxalic acid [(COOH)_(2) . 2H_(2) O] containing 12.6 g of the acid in 100 mL of the solution.

A bulb contains 1.6 g of O_(2) contains.

13.4 g of a sample of unstable hydrated salt Na_(2)SO_(4).XH_(2)O was found to contains 6.3 g of H_(2) O . The number of molecular of water of crystalistion is

14.2 g Na_2SO_4 is present in 10^2 kg water. Its concentration in ppm is

A 100 mL solution was made by adding 1.43 g of Na_(2)CO_(3). xH_(2)O . The normality of the solution is 0.1 N. The value of x is _______. ("The atomic mass of Na is 23 g/mol")

48 g of SO_(3) , 12.8 g of SO_(2) and 9.6 g of O_(2) are present in one litre . The respective active masses will be

The hydrated salt Na_2 SO_4. nH_2 O undergoes 56% loss in mass on heating and becomes anhydrous. The value of 'n' will be :