Given two straight lines x - y - 7 = 0 and x - y + 3 = 0. Equation of a line which divides the distance between them in the ratio 3:2 (internally) can be :

The straight lines x+y-4=0, 3x+y-4=0 and x+3y-4=0 form a triangle, which is

Given two straight lines 3x - 2y = 5 and 2x + ky + 7 =0 . Find the value of k for which the given lines are : parallel to each other.

The straight lines 3x+y-4=0,x+3y-4=0 and x+y=0 form a triangle which is :

The angle between the straight lines 2x-y+3=0 and x+2y+3=0 is-

The equation of the line which bisects the obtuse angle between the line x-2y+4=0 and 4x-3y+2=0 is

The ratio in which the line 3x+4y+2=0 divides the distance between the lines 3x+4y+5=0 and 3x+4y-5=0

Given three straight lines 2x+11 y-5=0,24 x+7y-20=0, and 4x-3y-2=0 . Then, a)they form a triangle b)one line bisects the angle between the other two c) two of them are parallel

Find the distance between the parallel lines 3x+4y-7=0 and 3x+4y+8=0 .

The equation of the straight line which bisects the intercepts between the axes of the lines x+y=2 and 2x + 3y = 6 is

Find the ratio in which the line 3x+4y+2=0 divides the distance between the lines 3x+4y+5=0a n d3x=4y-5=0.