`(dy)/(dx)=(x+1)^(3)+(2y)/(x+1)`

Let y=f (x) and x/y (dy)/(dx) =(3x ^(2)-y)/(2y-x^(2)),f(1)=1 then the possible value of 1/3 f(3) equals :

(dy)/(dx)=(x+y+1)/(2x+2y+3)

The solution of (dy)/(dx)=(x^2+y^2+1)/(2x y) satisfying y(1)=1 is given by

The solution of (dy)/(dx)=(x^2+y^2+1)/(2x y) satisfying y(1)=1 is given by

Solve: (i) sin^(-1)((dy)/(dx))=x+y (ii) (dy)/(dx)=cos(x+y) (iii) (dy)/(dx)=(4x+y+1)^2

Find (dy)/(dx), y=((x^2-1)^3(2x-1))/(sqrt((x-3)(4x-1)))

The solution of differential equation x^2=1 +(x/y)^(-1)(dy)/(dx)+((x/y)^-2((dy)/(dx))^2)/(2!)+((x/y)^(-3)((dy)/(dx))^3)/(3!)+... i s

x(x-1) (dy)/(dx) - (x-2) y = x^3 (2x-1)

Solve the initial value problem: y-x(dy)/(dx)=2(1+x^2(dy)/(dx)),\ y(1)=1

Find the order and degree of the following differential equations. i) (dy)/(dx)+y=1/((dy)/(dx)) , ii) e^(e^(3)y)/(dx^(3))-x(d^(2)y)/(dx^(2))+y=0 , iii) sin^(-1)(dy)/(dx)=x+y , iv) log_(e)(dy)/(dx)=ax+by v) y(d^(2)y)/(dx^(2))+x((dy)/(dx))^(2)-4y(dy)/(dx)=0