Value of `abs([(a+1)(a+2),(a+1),1],[(a+2)(a+3),(a+2),1],[(a+3)(a+4),(a+3),1])`

Find value of determinant of A =abs[[(a+1)(a+2),(a+2),1],[(a+3)(a+2),(a+3),1],[(a+3)(a+4),(a+4),1]]

The value of |((a+1)(a+2),a+2,1),((a+2)(a+3),a+3,1),((a+3)(a+4),a+4,1)| is

Locate the points: (1,1),(1,2),(1,3),(1,4) (2, 1),(2,2),(2,3),(2,4)(1,3),(2,3),(3,3),(4,3)(1,4),(2,4),(3,4),(4,4)

The value of 5-(2(1)/2-3/4)+(3(1)/2-1(1)/4)

The value of ((1)/(2)" of " 1(1)/(2))div(3(1)/(2)-1(1)/(4)) "of" 1(1)/(2)-1(1)/(2)div2(1)/(4)+1(1)/(3) is :

The value of ((1)/(2)" of "1(1)/(2))-:(3(1)/(2)-1(1)/(4))" of "1(1)/(2)-1(1)/(2)-:2(1)/(4)+1(1)/(3) is: