`int_(-1)^1 e^(2x+3) dx`

int_(-1)^(1)e^(2x)dx

Evaluate : int_(-1)^(1)e^(x)dx

int_(-1)^(2) e^(-x)dx

int_(1)^(2) (x^3+1) dx

Evaluate: int_0^1|5x-3|dx (ii) int_0^pi|cosx|dx (iii) int_(-5)^5|x-2|dx (iv) int_(-1)^1e^(|x|)dx (v) int_0^2|x^2+2x-3|dx (v) int_1^4(|x-1|+|x-2|+|x-3|)dx (vi) int_(-1)^2|x^3-x|dx

Evaluate int_-1^1 e^|x|dx

If int_(0)^(1) x e^(x^(2) ) dx=alpha int_(0)^(1) e^(x^(2)) dx , then

int_(1)^(e) (e^(x) (1+xlog x))/(x) dx

int_(1)^(3)e^(4x+1)dx

If I_(1)=int_(0)^(1) 2^(x^(2)) dx, I_(2)=int_(0)^(1) 2^(x^(3)) dx, I_(3)=int_(1)^(2) 2^(x^(2))dx and I_(4)=int_(1)^(2) 2^(x^(3))dx then