For 100% modulation the power carried by the side bands `(P_(sB))_`( is given by )

Fraction of total power carried by the side bands (P_(S)//P_(T)) is given by

When m=1 ,power carried by side bands is:

Fraction of total power carried by side bands is given by-

The total power content of an AM signal is 3000 w. For 100% modulation, the power of CW and that of each side band are,

In AM wave total power of side bands is given by :

The modulation index is 0.75. Then the useful power available in the side bands nearly

In an amplitude modulation with modulation index 0.5 the ratio of the carrier wave to that of side band in the modulated wave is

A carrier wave of 1000 W is subjected to 100% modulation. Calculate (i) Power of modulated wave, (ii) Power in USB, (iii) Power in LSB.

An AM wave has 1800 watt of total power content, For 100% modulation the carrier should have power content equal to