Two forces each of magnitude 2N, act at an angle of `60^(@)`. The magnitude of the resultant force

Two forces of magnitudes P and Q are inclined at an angle (theta) . The magnitude of their resultant is 3Q. When the inclination is changed to (180^(@)-theta) , the magnitude of the resultant force becomes Q. Find the ratio of the forces.

Two forces with equal magnitudes F act on a body and the magnitude of the resultant force is F /3. The angle between the two forces is

Find the magnitude of the resultant of shown forces :-

Two equal forces are acting at a point with an angle of 60^(@) between them. If the resultant force is equal to 40sqrt(3)N , The magnitude of each force is :-

Two equal forces (P each) act at a point inclined to each other at an angle of 120^@ . The magnitude of their resultant is

The resultant of two forces has magnitude 20N. One of the forces is of magnitude 20sqrt(3)N and makes an angle of 30^(@) with the resultant. Then what is the magnitude of the other force?

A body of mass 2kg is acted by two forces each of magnitude 1 newton, making an angle of 60^(@) with each other. The net acceleration of the body ("in" m//s^(2) ) is

Two forces of mangitude F_(1) and F_(2) are acting on an object.The magnitude of the net force F_(n e t ) on the object will be in the range.

Two equal forces are acting at a point with an angle 60^(@) between them. If the resultant force is equal to 4sqrt(3)N , the magnitude of each force is

Two forces of magnitude 3N and 4N respectively are acting on a body. Calculate the resultant force if the angle between them is 0^(@)