If `f(x)=x^2-1` and `g(x)=(x+1)/2`, then `f(3)/(f(3)+g(3))`

If f(x)=x^2 and g(x)=x^2+1 then: (f@g)(x)=(g@f)(x)=

If f(x)=3x+1 and g(x)=x^(3)+2 then ((f+g)/(f*g))(0) is:

If f(x)=(x-2)^2 and g(x) =3x-3 then: (f@g)(2)=

If f(x)=1+2x and g(x) = x/2 , then: (f@g)(x)-(g@f)(x)=

If f(x)=x^(2) and g(x)=2x , then evaluate, (i) (f+g)(3)" "(ii) (f-g)(2) (iii) (f*g)(1)" "(iv) ((f)/(g))(5)

If f and g are real functions defined by "f(x)=2x-1" and g(x)=x^(2) then (A) (3f-2g)(1)=1 (B) (fg)(2)=10 (C) g^(3)(2)=128 (D) ((sqrt(f))/(g))(2)=(sqrt(3))/(2)

If, from RtoR,f(x)=(x+1)^2 and g(x)=x^2+1, then: (f@g)(-3)=

If f(x) = 3x + 1 and g(x) = x^(2) - 1 , then (f + g) (x) is equal to

If f (x) =(x^(2) -1) " and " g (x) =(2x +3) " then " (g o f) (x) =?

If the functions of f and g are defined by f(x)=3x-4 and g(x)=2+3x then g^(-1)(f^(-1)(5))