Given `A(6,0)` and `B(0,4)` and O is the origin.If the locus `P` such that area of `Delta POB`=2 (area of `Delta POA`) is `x^(2)-ky^(2)=0` ,then `k` is equal to

The coordinates of three points O, A, B are (0, 0), (0,4) and (6, 0) respectively. A point P moves so that the area of Delta POA is always twice the area of Delta POB . Find the equation to both parts of the locus of P.

Let Delta denote the area of the DeltaABCand Delta p be the area of its pedal triangle. If Delta=k Deltap, then k is equal to

In the figure, given alongside, PB and QA are perpendiculars to the line segment AB. If PO = 6 cm, QO = 9 cm and area of Delta POB - 120 cm^2 . find the area of Delta QOA .

If Delta_1=|(1,0),(a,b)| and Delta_2=|(1,0),(c,d)| , then Delta_2Delta_1 is equal to :

Let A (0,2 ) , B ( 3, 0 ) , C ( 6, 4 ) be the vertices of triangle and P is a point inside the triangle such that area of triangle APB, BPC and CPA are equal. Equation of circle circumscribing Delta APB is :

Using determinats, find the values of k, if the area of triangle with vertices (-2, 0), (0, 4) and (0, k) is 4 square units.

If the area of the triangle formed by the pair of lines 8x^2 - 6xy + y^2 = 0 and the line 2x+3y=a is 7 then a=

The ends of the base of an isosceles triangle are (2sqrt(2), 0) and (0, sqrt(2)) . One side is of length 2sqrt(2) . If Delta be the area of triangle, then the value of [Delta] is (where [.] denotes the greatest integer function)

Find the area of the triangle formed by the line x+y=3 and the angle bisectors of the pair of lines x^2-y^2+4y-4=0

Let O-=(0,0),A-=(0,4),B-=(6,0)dot Let P be a moving point such that the area of triangle P O A is two times the area of triangle P O B . The locus of P will be a straight line whose equation can be