The line y=6x+1 touches the parabola `y^(2)=24x`. The coordinates of a point P on this line, from which the tangent to `y^(2) =24x` is perpendicular to the line y=6x+1. is

The line 4x+6y+9 =0 touches the parabola y^(2)=4ax at the point

If the line y=mx+c touches the parabola y^(2)=4a(x+a) , then

If the line y=mx+c touches the parabola y^(2)=4a(x+a) , then

The line x+y=6 is normal to the parabola y^(2)=8x at the point.

If the line x + y = 1 touches the parabola y^2-y + x = 0 , then the coordinates of the point of contact are:

Find the equation of the tangent of the parabola y^(2) = 8x which is perpendicular to the line 2x+ y+1 = 0

The equation of the tangent to the parabola y^(2)=8x which is perpendicular to the line x-3y+8=0 , is

Write the coordinates of the point at which the tangent to the curve y=2x^2-x+1 is parallel to the line y=3x+9 .

The equation of a tangent to the parabola y^2=""8x"" is ""y""=""x""+""2 . The point on this line from which the other tangent to the parabola is perpendicular to the given tangent is

Find the point on the curve y=3x^2+4 at which the tangent is perpendicular to the line whose slope is -1/6 .