Solve `cosmtheta=cosntheta`

If A=[(cos theta, sin theta),(-sin theta, cos theta)] , then prove that A^n=[[cosntheta,sin ntheta],[-sin ntheta,cos ntheta]], n in N

If A^(n)={:[(cosntheta,sinntheta),(-sinntheta,cosntheta)]:} then the matrix B satisfying AB=BA=I is

If (costheta+isintheta)(cos2theta+isin2theta)…..(cosntheta+isinntheta)=1 , then the value of theta , is

Solve the questions

If A=[[costheta,isintheta],[isintheta,costheta]], then prove by principal of mathematical induction that A^n=[[cosntheta, i sinn theta],[isin n theta, cos n theta]] for all nin NN.

Solve the inequation

Solve the following

Solve the following