Area bounded by curve `y^(2)=x`and x=4 is divided into 4 equal parts by the lines x=a and y=b then a& b is

The area between x=y^2 and x = 4 is divided into two equal parts by the line x = a , find the value of a.

Area bounded by the curves y=x^2 - 1 and x+y=3 is:

The area bounded by the curve y=4-x^(2) and X-axis is

The area bounded by the curve y^(2)=x and the ordinate x=36 is divided in the ratio 1:7 by the ordinate x=a. Then a=

Area bounded by the curves y=|x-1|, y=0 and |x|=2

The area bounded between curves y^2 = x and y= |x|

The area bounded by the curve y=x^2 , the x-axis and the line x=2^(1/3) is divided into two equal areas by the line x=k . The value of k is (A) 2^(-2/3) (B) 2^(-1/3) (C) 1 (D) 2^(1/3)-1

The area bounded by the curve x^(2)=4y and the line x=4y-2 is

The area bounded by the curve y=3/|x| and y+|2-x|=2 is

The area bounded by the curve x^(2)=4ay and the line y=2a is