`(x-1)(x^2+2x+1)-(x+1)(x^2-2x+1)`

(x^2+2x+1)(x^2-x+1)

Solve for x : (x - 1)/(2x + 1) + (2x + 1)/(x -1) = 2 , where x ne - (1)/(2) , 1

Express the following in the lowest terms. ((2x^(2)+1)/(x-1)+(x-1)/(x+1))xx((x^(2)-1)/(2x)):

If f(x) =|(1, x, x+1),(2x, x(x-1), x(x+1)), (3x(x-1), 2(x-1)(x-2), x(x+1)(x-1))| then what is f(-1) +f(0) +f(1) equal to ?

If f(x)=|[1,2(x-1),3(x-1)(x-2)],[x-1,(x-1)(x-2),(x-1)(x-2)(x-3)],[x,x(x-1),x(x-1)(x-2)]| . Then, the value of f(2020) is

(2x-1)/(2x+1)+(2x+1)/(2x-1)=6

(x-2)^(2),(x-1)^(2),x^(2)(x-1)^(2),x^(2),(x+1)^(2)x^(2),(x+1)^(2),(x+2)^(2)]|=-8