Simplify `1+tantheta.tan(theta/2)`

Simplify tan theta [(sectheta,tantheta),(tantheta,-sectheta)]+sectheta[(-tantheta,-sectheta),(-sectheta,tantheta)]

Simplify sec theta[[tan theta,sec theta],[sec theta,-tan theta]] - tan theta[[sec theta,tan theta],[tan theta,-sec theta]]

Solve: tan3theta+tantheta=0

If sintheta=(3)/(5) ,verify that (tantheta)/(1+tan^(2)theta)=sinthetacostheta .

Simplify: (1+tan^(2)theta)(1-sintheta)(1+sintheta)

Simplify (1 + tan ^(2) theta ) ( 1 + sin theta ) ( 1 - sin theta )

tantheta .tan(90^(@) - theta) =

Solve: tan^(3)theta-3tantheta=0

What is (2tantheta)/(1+tan^(2)theta) equal to ?