Simplify `tan^2theta/(tantheta-1)+1/(tantheta(1-tantheta))`

sec^2theta/tantheta=?

(sectheta+tantheta-1)(sectheta-tantheta+1)=

Simplify tan theta [(sectheta,tantheta),(tantheta,-sectheta)]+sectheta[(-tantheta,-sectheta),(-sectheta,tantheta)]

costheta(tantheta+2)(2tantheta+1)=?

(tantheta+2)(2 tantheta+1)= ?

If A=[(1,-tantheta),(tantheta, 1)] [(1,tantheta),(-tantheta,1)]^-1 = [(a,-b),(b,a)] then (A) a=b=-1 (B) a=sin2theta, b=cos2theta (C) a=cos2theta, b=sin2theta (D) none of these

The value of (2cos^(2)theta-1)((1+tantheta)/(1-tantheta)+(1-tantheta)/(1+tantheta)) is

tantheta+tan2theta=tanthetatan2theta=1

(tantheta+sectheta-1)/(tantheta-sectheta+1)=