`N_(2)O_(4)(g)` can dissociate into `NO_(2)(g)` if dissociates by `75%` then the observed vapor density of `N_(2)O_(4)` will be approximately

If "66%" of "N_(2)O_(4)(g)" is dissociated into "NO_(2)(g)" at "27^(@)C" and "1" atm pressure,the volume occupied by 11.5g" of "N_(2)O_(4)" would be about

The ratio of the rate of diffusion of a sample of N_(2)O_(4) partially dissociated in to NO_(2) to pure hydrogen was found to be 1:5 . Calculate the degree of dissociation of N_(2)O_(4) .

For the reaction , N_2O_4(g) hArr2NO_2(g) , if percentage dissociation of N_2O are 25% , 50% , 75% and 100, then the sequence of observed vapour densities will be

For the reaction N_2O_4 hArr 2NO_2(g) , if percentage dissociation of N_2O_4 are 20%, 45%, 65%, 80% then the sequence of observed vapour densities wil be :

N_(2)O_(4) dissociates into NO_(2) . If % dissociation of N_(2)O_(4) is 33.33 % , calculate average molecular weight of gaseous mixture formed.

N_(2)O_(4) is 60% dissociated into NO_(2) at 340K and 1 atm pressure. Find the volume of 10 g N_(2)O_(4) occupy under these condition.

In the dissociation of N_(2)O_(4) into NO_(2). (1+x) values with the vapour densities ratio ((D)/(d)) is given by :

N_(2)O_(4)(g) is dissociated to an extent of 20% at equilibrium pressure of 1.0 atm and 57^(@)C . Find the percentage of N_(2)O_(4) at 0.2 atm and 57^(@)C .