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If (omega != 1) is a cube root of unity ...

If `(omega != 1)` is a cube root of unity and `omega` and `omega^2` satisfy the equation `1/(a+x)+1/(b+x)+1/(c+x)+1/(d+x)=2/x` then value of `1/(a+1)+1/(b+1)+1/(c+1)+1/(d+1)` is

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