`int_(0)^( pi)|cos theta-sin theta|d theta=`

Evaluate: int_0^(pi//2)sqrt(costheta)sin^3theta d theta

sin theta -cos theta=0

int_0^(pi//2)(theta/sintheta)^2d theta=

Evaluate: intcos 2 theta ln((cos theta+sin theta)/(cos theta-sin theta))d theta

The value of the integral int_(0)^(2pi)(sin2 theta)/(a-b cos theta)d theta when a gt b gt 0 , is

Let f beintegrable over [0,a] for any real value of a . If I_(1)=int_(0)^(pi//2)cos theta f(sin theta +cos^(2) theta) d theta and I_(2)=int_(0)^(pi//2) sin 2 theta f(sin theta+cos^(2) theta) d theta , then

Show that int_0^(pi/2)sqrt((sin2theta))sintheta d theta=pi/4

Show that int_0^(pi/2)sqrt((sin2theta))sintheta d theta=pi/4

Evaluate : int (2 sin 2 theta- cos theta)/(6 - cos^(2) theta- 4 sin theta) d theta

The value of I(n) =int_0^pi(sin ^2n theta)/(sin^2theta) d theta is (AA n in N)