`(x^(3)y^(2)+xy)dx=dy`

Solve the differential equations x^(2)dy-(x^(2)+xy-2y^(2))dx=0

By substituting y = vx, the solution of the differential equation (dy)/(dx)-(x^(2)+y^(2))/(xy)=0 , is

Solve the differential equation : (dy)/(dx)=(x^(2)-y^(2))/(xy) .

The differential equations of all circle touching the x-axis at orgin is (a) (y^(2)-x^(2))=2xy((dy)/(dx)) (b) (x^(2)-y^(2))(dy)/(dx)=2xy ( c ) (x^(2)-y^(2))=2xy((dy)/(dx)) (d) None of these

y(xy+1)dx+x(1+xy+x^(2)y^(2))dy=0

If (y^(3)-2x^(2)y)dx+(2xy^(2)-x^(3))dy=0, then the value of xysqrt(y^(2)-x^(2)), is

Solve (x^(2) + y^(2))(dy)/(dx) = 2xy

If m, n are order and degree of differential equation y(dy)/(dx) + x^(3)((d^(2)y)/(dx^(2)))-xy = cos x then

Show that (3xy + x^(2)) dy + (y^(2) + xy)dx = 0 is homogeneous differential equation. Also find its general solution.

Find the general solution of y^(2)dx+(x^(2)-xy+y^(2))dy=0