`(1+x^2)dy/dx+2xy-x^3=0`

Solve: (1+x^2)(dy)/(dx)+2xy-4x^2=0 subject to the initial condition y(0)=0.

dy/dx+2xy=e^(-x^2)

(1-x^(2))(dy)/(dx)-2xy=x-x^(3)

(1-x^(2))(dy/dx)+xy=xy^(2)

IF of the following differential equations. (1-x ^2)(dy //dx) + 2xy = x ( 1- x^2 ) ^(1//2)

Solve: (1+x^2)(dy)/(dx)+2xy=cosx

Find the particular solution of the differential equation (1+x^(2))(dy)/(dx)+2xy=(1)/(1+x^(2)) given that at x=1 , y=0 .

x^2(dy/dx)^2-2xy dy/dx+2y^2-x^2=0

Solve the following differential x^2(dy/dx)^2-2xy dy/dx+2y^2-x^2=0

The solution of the differential equation (x^2y^2-1)dy+2xy^3dx=0 is