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If A=(0.216 +0.008)/(0.36+0.04-0.12) and...

If `A=(0.216 +0.008)/(0.36+0.04-0.12)` and `B=(0.729 - 0.027)/(0.81+ 0.09 +0.27)`, then what is the value of `(A^2+B^2)^2` ?

A

0.8

B

1

C

2.2

D

1.44

Text Solution

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The correct Answer is:
B
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