Energy consumed by heater in 5 min, when the current flowing through heater is 5A and resistance is 44 `Omega`.

Options

A. `4.5xx10^5J`
B. `3.0xx10^5J`
C. `4xx10^5J`
D. `3.3xx10^5J`

Explanation

To find the energy consumed by a heater in 5 minutes when the current flowing through it is 5 A and the resistance is 44 Ω, we can follow these steps:

### Step 1: Identify the formula for power
The power (P) consumed by an electrical device can be calculated using the formula:
\[ P = I^2 \times R \]
where:
- \( I \) is the current in amperes (A)
- \( R \) is the resistance in ohms (Ω)

### Step 2: Substitute the values for current and resistance
Given:
- \( I = 5 \, A \)
- \( R = 44 \, Ω \)

Substituting these values into the power formula:
\[ P = (5)^2 \times 44 \]

### Step 3: Calculate the power
Calculating the above expression:
\[ P = 25 \times 44 = 1100 \, W \]
So, the power consumed by the heater is 1100 watts (W).

### Step 4: Convert time from minutes to seconds
The time (t) is given as 5 minutes. We need to convert this into seconds:
\[ t = 5 \, \text{minutes} \times 60 \, \text{seconds/minute} = 300 \, \text{seconds} \]

### Step 5: Calculate the energy consumed
The energy (E) consumed can be calculated using the formula:
\[ E = P \times t \]
Substituting the values we have:
\[ E = 1100 \, W \times 300 \, s \]

### Step 6: Perform the multiplication
Calculating the energy:
\[ E = 1100 \times 300 = 330000 \, J \]

### Step 7: Express the energy in scientific notation
The energy can also be expressed in scientific notation:
\[ E = 3.3 \times 10^5 \, J \]

### Final Answer
The energy consumed by the heater in 5 minutes is \( 330000 \, J \) or \( 3.3 \times 10^5 \, J \).

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