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Two capacitors C(1) and C(2) are charged...

Two capacitors `C_(1) and C_(2)` are charged to 120V and 200V, respectively. It is found that by connecting them together, the potential on each one can be made zero. Then

A

`5C_1=3C_2`

B

`3C_1=5C_2`

C

`3C_1+5C_2=0`

D

`9C_1=4C_2`

Text Solution

Verified by Experts

The correct Answer is:
B
`3C_1=5C_2`
Explanation: `V=(q_1-q_2)/(C_1+C_2)`
`=(C_1V_1-C_2V_2)/(C_1+C_2)`
But `V_1=120V,V_2=200V,V=0 and C_1+C_2 ne oo`
`C_1V_1-C_2V_2=0`
`C_1V_1=C_2V_2`
`120C_1=200C_2`
`3C_1=5C_2`
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