An electron is accelerated through the potential difference of 3000 V.
Energy acquire by electron:

Options

A. `4.86xx10^(-16)J`
B. `4.3xx10^(-16)J`
C. `1.6xx10^(-19)J`
D. `3.2xx10^(-16)J`

Explanation

To find the energy acquired by an electron when it is accelerated through a potential difference of 3000 V, we can use the formula:

\[ \text{Energy (E)} = \text{Charge (q)} \times \text{Potential Difference (V)} \]

### Step 1: Identify the charge of the electron
The charge of an electron is a known constant:
\[ q = 1.6 \times 10^{-19} \text{ coulombs} \]

### Step 2: Identify the potential difference
The potential difference through which the electron is accelerated is given as:
\[ V = 3000 \text{ volts} \]

### Step 3: Substitute the values into the formula
Now, we can substitute the values of charge and potential difference into the formula to calculate the energy:
\[ E = q \times V \]
\[ E = (1.6 \times 10^{-19} \text{ C}) \times (3000 \text{ V}) \]

### Step 4: Perform the multiplication
Calculating the energy:
\[ E = 1.6 \times 10^{-19} \times 3000 \]
\[ E = 1.6 \times 3 \times 10^{-16} \]
\[ E = 4.8 \times 10^{-16} \text{ joules} \]

### Conclusion
The energy acquired by the electron when accelerated through a potential difference of 3000 V is:
\[ E = 4.8 \times 10^{-16} \text{ joules} \]

### Final Answer
The correct option is \( 4.8 \times 10^{-16} \) joules.

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