The work done in moving a charge of 5 C starting from one point A and ends at the same point is ?

Options

A. 5J.
B. 10J.
C. Zero.
D. 2.5 J.

Explanation

To solve the problem of calculating the work done in moving a charge of 5 C from point A back to point A, we can follow these steps:

### Step 1: Understand the Concept of Work Done
The work done (W) in moving a charge (Q) in an electric field is given by the formula:
\[ W = Q \times \Delta V \]
where \( \Delta V \) is the change in electric potential (voltage) between the two points.

### Step 2: Identify the Initial and Final Points
In this case, the charge is moved from point A to point A. Therefore, the initial and final points are the same.

### Step 3: Calculate the Change in Potential Difference
Since the charge starts and ends at the same point, the potential difference (\( \Delta V \)) is:
\[ \Delta V = V_A - V_A = 0 \]
This means there is no change in potential difference.

### Step 4: Substitute the Values into the Work Done Formula
Now, substituting the values into the work done formula:
\[ W = Q \times \Delta V = 5 \, \text{C} \times 0 \]
\[ W = 0 \, \text{Joules} \]

### Step 5: Conclusion
The work done in moving the charge of 5 C from point A back to point A is:
\[ W = 0 \, \text{Joules} \]

### Final Answer
The work done is **0 Joules**.

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