Calculate the force on an charge of 3C in a uniform electric field of `5 xx 10^(4)NC^(-1)`?

Options

A. `15 xx 10^(4)N`
B. `7 xx 10^(-20)`
C. `1.87 xx 10^(10)`
D. `6.7 xx 10^(-10)`

Explanation

To solve the problem of calculating the force on a charge of 3C in a uniform electric field of \(5 \times 10^4 \, \text{N/C}\), we can follow these steps:

### Step 1: Understand the formula for electric force
The force \(F\) experienced by a charge \(q\) in an electric field \(E\) is given by the formula:
\[ F = q \times E \]
where:
- \(F\) is the force in Newtons (N),
- \(q\) is the charge in Coulombs (C),
- \(E\) is the electric field strength in Newtons per Coulomb (N/C).

### Step 2: Identify the given values
From the question, we have:
- Charge \(q = 3 \, \text{C}\)
- Electric field \(E = 5 \times 10^4 \, \text{N/C}\)

### Step 3: Substitute the values into the formula
Now, we can substitute the values of \(q\) and \(E\) into the formula:
\[ F = 3 \, \text{C} \times 5 \times 10^4 \, \text{N/C} \]

### Step 4: Perform the multiplication
Calculating the multiplication:
\[ F = 15 \times 10^4 \, \text{N} \]

### Step 5: Write the final answer
Thus, the force acting on the charge of 3C in the electric field is:
\[ F = 15 \times 10^4 \, \text{N} \]

### Conclusion
The correct answer is \(15 \times 10^4 \, \text{N}\).

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