Calculate the capacitance value if the electric charge is 80C and a potential difference is 4V?

Options

A. 22 F.
B. 4.4 F
C. 65 F.
D. 20 F.

Explanation

To calculate the capacitance value given the electric charge and potential difference, we can use the formula:

\[ C = \frac{Q}{V} \]

where:
- \( C \) is the capacitance in Farads (F),
- \( Q \) is the electric charge in Coulombs (C),
- \( V \) is the potential difference in Volts (V).

### Step-by-Step Solution:

1. **Identify the given values**:
- Electric charge \( Q = 80 \, \text{C} \)
- Potential difference \( V = 4 \, \text{V} \)

2. **Substitute the values into the capacitance formula**:
\[ C = \frac{Q}{V} = \frac{80 \, \text{C}}{4 \, \text{V}} \]

3. **Perform the calculation**:
\[ C = \frac{80}{4} = 20 \, \text{F} \]

4. **Conclusion**:
The capacitance value is \( 20 \, \text{F} \).

### Final Answer:
The capacitance value is **20 Farads**.

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