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Intensity of electric field at a point a...

Intensity of electric field at a point at a perpendicular distance .r. from an infinite line charge, having linear charge density `.lambda.` is given by :

A

`E=((1)/(4pi epsilon_(0))) (lambda)/( r)`

B

`E=((1)/(4pi epsilon_(0))) (2lambda)/( r)`

C

`E=((1)/(4pi epsilon_(0))) (lambda)/( r^(2))`

D

`E=((1)/(4pi epsilon_(0))) (2lambda)/( r^(2))`

Text Solution

Verified by Experts

The correct Answer is:
B
The electric field due to an infinite line of charge density `lambda` is
`E=((1)/(4pi epsilon_(0))) (2lambda)/(r )`
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