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The equivalent capacity of two capacitor...


The equivalent capacity of two capacitors in series is `3muF` and in parallel is `16muF`. Their individual capacities are

A

12,4

B

8,8

C

10,16

D

12,2

Text Solution

Verified by Experts

The correct Answer is:
A
`C_(p) = C_(1) +C_(2) =16muF`
`C_(s) =(C_(1)C_(2))/(C_(1)+C_(2)) =3muF`
or `C_(1)C_(2) =3(C_(1)+C_(2)) =3 xx 16 =48muF`
or `C_(1)(16-C_(1))=48`
`:.C_(1) =12muF , C_(2) =4muF`
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