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Two bulbs B(1) and B(2) are connected i...

Two bulbs `B_(1)` and `B_(2)` are connected in series with an source of emf 250 V as shown in the figure 15 below. The labels on the bulbs read 250 V, 80 W and 250 V, 100 W respectively.

What will be the ratio of the resistance of the bulbs `R_(1)//R_(2)`?

Text Solution

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The correct Answer is:
A
`R_(1)=(V_(1)^(2))/(P_(1)) , R_(2) =(V_(2)^(2))/(P_(2))`
`(R_(1))/(R_(2)) =((V_(1))/(V_(2)))^(2) *(P_(2))/(P_(1))`
`=((250)/(250))^(2) xx (100)/(80)=(5)/(4)`
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