1. PROVE `sin^2(pi/6)+cos^2(pi/3)-tan^2(pi/4)=-1/2`

Prove that (a) sin^(2)(pi/6) + cos^(2)( pi/3) - tan^(2)(pi/4) = -1/2 (b) sin((8pi)/3) cos((23pi)/6) + cos((13pi)/3) sin((35pi)/6) = 1/2

" 1.Prove that : "sin^(2)(pi)/(6)+cos^(2)(pi)/(3)-tan^(2)(pi)/(4)=-(1)/(2)

Prove that: (sin^(2)pi)/(6)+(cos^(2)pi)/(3)-tan^(2)(pi)/(4)=-(1)/(2)

"sin"^(2)(pi)/(6)+"cos"^(2)(pi)/(3)-"tan"^(2)(pi)/(4)+(1)/(2) is:

"sin"^(2)(pi)/(6)+"cos"^(2)(pi)/(3)-"tan"^(2)(pi)/(4)+(1)/(2) is:

Find the value of the sin^(2)((pi)/(6))+cos^(2)((pi)/(3))-tan^(2)((pi)/(4))

sin^(2)(pi)/(6)+cos^(2)(pi)/(3)-tan^(2)-(1)/(2)(pi)/(4)=-(1)/(2)

Show / Prove/ Verify the following : (sin^(2)""(pi)/(6)+cos^(2)""(pi)/(3)+tan^(2)""(pi)/(6))/(sec^(2)""(pi)/(4)-cos^(2)pi)=(1)/(3).cos""(pi)/(3)+(1)/(sqrt3)sec""(pi)/(6)

2(sin^(2)(pi/6)) +"cosec"(7pi)/(6)cos^(2)pi/3=3/2

The value of 2sin^(2)((pi)/(3))-cos^(2)((pi)/(6))+tan^(2)(pi/6) is equal to ....