Particle's position as a function of time is given by `x=t^3-3t^2+6`. then maximum value of `x` occurs when t=.....

The particle's position as a funciton of time is given as x=5t^2-9t+3 . Find out the maximum value of position co-ordinate? Also, plot the graph.

A particle moves along a straight line and its position as a function of time is given by x = t6(3) - 3t6(2) +3t +3 , then particle

Under the action of foece, 1 kg body moves such that its position x as a function of time t is given by x=(t^(3))/(3), x is meter. Calculate the work done (in joules) by the force in first 2 seconds.

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in meter and t in second. The work done by the force in the first two seconds is .

Under the action of a force, a 2 kg body moves such that its position x as a function of time is given by x =(t^(3))/(3) where x is in metre and t in second. The work done by the force in the first two seconds is .

A foce acts on a 30g particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where x is in metre and t in second. The work done during the first 4s is

The position of a particle as a function of time t, is given by x(t)=at+bt^(2)-ct^(3) where a,b and c are constants. When the particle attains zero acceleration, then its velocity will be :

A force acts on a 3.0 gm particle in such a way that the position of the particle as a function of time is given by x=3t-4t^(2)+t^(3) , where xx is in metres and t is in seconds. The work done during the first 4 seconds is

A point moves such that its displacement as a function of time is given by x^3 = t^3 + 1 . Its acceleration as a function of time t will be

The displacement x of a particle along the x-axis at time t is given by x=a_1/2t+a_2/3t^2 . Find the acceleration of the particle.