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Arrange the following compounds in increasing order of basicity : 1) (P) (Q) (Q) (Q) (Q) ( (I) (I) (I) (I) (I) (I) (I) (I) (I) (I) (I) (I) (I) (I) (I) (I) (I) (I)

The value of i^(i) , is

Convert the following points from polar coordinates to the corresponding Cartesian coordinates. (i) ( i i ) (iii)(( i v ) (v)2, (vi)pi/( v i i )3( v i i i ) (ix) (x))( x i ) (xii) (ii) ( x i i i ) (xiv)(( x v ) (xvi)0, (xvii)pi/( x v i i i )2( x i x ) (xx) (xxi))( x x i i ) (xxiii) (iii) ( x x i v ) (xxv)(( x x v i ) (xxvii)-sqrt(( x x v i i i )2( x x i x ))( x x x ) , (xxxi)pi/( x x x i i )4( x x x i i i ) (xxxiv) (xxxv))( x x x v i ) (xxxvii)

Find the value of i^(4) + i^(5) + i^(6) + i^(7) .

Convert the following in the form of (a+ib) : (i) (1+i)^(4) (ii) (-3+(1)/(2)i)^(3) (iii) (1-i)(3+4i) (iv) (1+i)(1+ 2i)(1+ 3i) (v) (3+5i)/(6-i) (vi) ((2+3i)^(2))/(2+i) (vii) ((1+ i)(2+i))/((3+i)) (viii) (2-i)^(-3)

Simplify the following : (i) i^(97) (ii) i^(8) (iii) (1)/(i^(3)) (iv) (-i)^(14) (v) i^(-22) (vi) i^(-63)

Convert the following polar coordinates to its equivalent Cartesian coordinates. (i) ( i i ) (iii)2,pi)( i v ) (v) (ii) ( v i ) (vii)(( v i i i ) (ix)sqrt(( x )2( x i ))( x i i ) , (xiii)pi/( x i v )6( x v ) (xvi) (xvii))( x v i i i ) (xix) (iii) ( x x ) (xxi)(( x x i i ) (xxiii)-3,-( x x i v )pi/( x x v )6( x x v i ) (xxvii) (xxviii))( x x i x ) (xxx)

If I_(n)=int_(0)^(pi//4) tan^(n)x dx , then (1)/(I_(2)+I_(4)),(1)/(I_(3)+I_(5)),(1)/(I_(4)+I_(6)),... from\

the value of ((i^(11)+i^(12)+i^(13)+i^(14) +i^(15)))/((1+i)) is

If A^2-A +I = 0 , then the inverse of A is: (A) A+I (B) A (C) A-I (D) I-A