A ray of light enters into a thick glass slab from air as shown if figure.The refractive index of the glass slab varies with the depth x form the topmost surface of the slab as `mu`=`sqrt(3)`-`(1)/(sqrt(3))x`,sufficiently large thickness.Find the maximum depth reached by the ray inside the slab

When a ray of light enters a glass slab from air

When a ray of light enters a glass slab from air.

A ray of light 10^(-9) second to cross a glass slab of refractive index 1.5. The thickness of the slab will be

A ray of light strikes a glass slab (R.l. = mu ) of finite thickness t. The emerging light is

A light ray falls on a rectangular glass slab as shown. The index of refraction of the glass, if total internal reflection is to occur at the vertical face, is

A ray of light is incident on a glass slab at grazing incidence. The refractive index of the material of the slab is given by mu=sqrt((1+y) . If the thickness of the slab is d=2m , determing the equation of the trajectory of the ray inside the slab and the coordinates of the point where the ray exits from the slab. Take the origin to be at the point of entry of the ray.

Light enters in a glass slab of refractive index 3/2 and covers a distance 20 cm. The optical path of it is

A ray of light of wavelength u_(0) and frequency v_(0) enters a glass slab of refractice index mu from air. Then

A ray of light falls normally on a glass slab. Draw a diagram showing the path of the ray till it emerges out of the slab. What is the angle of incidence and angle of refraction at each surface of slab ?

Consider a ray of light incident from air onto a slab of glass (refractive index n) of width d, at an angle theta . The phase difference between the ray reflected by the top surface of the glass and the bottom surface is