A box of mass 20 kg is pushed along a rough floor with a velocity 2m/s and then let go. The box moves 5 m on the floor before coming to rest. What must be the frictional force acting on the box?
(1) 4 N
(2) 2 N
(3) 20 N
(4) 8 N

A body of mass 10 kg moves on rough horizontal surface with initial velocity 10m/s and travels 500m before coming to rest. The coefficient of friction is

A block of mass 20kg is placed on a rough horizontal plane and a horizontal force of 12N is applied. If coefficient of friction is 0.1 the frictional force acting on it is,

A body of mass 20 kg is kept initially at rest. A force of 80 N is applied on the body then the acceleration produced in the body is 3 m//s^(2) , force of friction acting on the body is :

A block of mass 20kg is pushed with a horizontal force of 90N. If the coefficient of static & kinetic friction are 0.4 & 0.3, the frictional force acting on the block is: (g =10ms^(-2) )

A block of mass 2 kg is kept on a rough horizontal floor an pulled with a force F. If the coefficient of friction is 0.5. then the minimum force required to move the block is :-

A block of mass 2 kg is at rest on a floor . The coefficient of static friction between block and the floor is 0.54. A horizonatl force of 2.8 N is applied to the block . What should be the frictional force between the block and the floor ? ( take , g = 10 m//s^(2) )

A body of mass 5 kg is moving with a velocity of 20 m/s. If a force of 100 N is applied on it for 10 s in the same direction as its velocity, what will be the velociy of the body ?

A heavy box is slid across a rough floor with an initial speed of 4 m/s. It stops moving after 8 seconds. If the average resisting force of friction is 10 N, the mass of the box (in kg) is

A vehicle of mass 500 kg is moving with a velocity of 15ms^(-1) . It is brought to rest by a retarding force. Find the distance moved by the vehicle before coming to rest, if the sliding friction between the tyres and the road is 3000N.