tanA = tanB + tanC, then find the relationship between A, B , C

tanA +tanB + tanC = tanA tanB tanC if

In a triangle ABC, tanA+tanB+tanC=6 and tanA. tan B = 3, then find the nature of triangle.

If 2tanA = 3tanB = 1, then what is tan(A-B) equal to?

In triangle A B C ,tanA+tanB+tanC=6a n dtanAtanB=2, then the values of tanA ,tanB ,tanC are, respectively (a)1,2,3 (b) 3,2//3,7//3 (c)4,1//2 ,3//2 (d) none of these

In a triangle ABC, tanA + tanB + tanC = 9. If tan^2 A+ tan^2 B + tan^2 C= k then the least value of k^(9/7) is

If cosA=tanB, cos B=tanC, cosC=tanA, then sin A is equal to

If A and B are acute angles such that tanA=(1)/(3) , tanB=(1)/(2) and tan(A+B)=(tanA+tanB)/(1-tanAtanB) , Then find the value of A+B .

If tanA+tanB+tanC=tanA.tanB.tanC , then-

If tanA=m/(m-1) and tanB=1/(2m-1) , find the value of (tanA-B) .

If A + B + C = 180^o then find tanA + tanB + tanC =