`dy/dx =-1/(sinx+cosx)^2`

Find (dy)/(dx), y=(sinx)^(cosx)+(cosx)^(sinx)

ysinx dy/dx=(sinx-y^2)cosx

find dy/dx if y= sinx.cosx

Find dy/dx if y= sinx/cosx

Find dy/dx if y= sinx.cosx

Find dy/dx If y= (sinx)^cosx .

Verify that the function defined by y = sinx - cosx is a solution of the initial value problem dy / dx = sinx +cosx ; such that y(0) = -1

If I_(n)=int(sinx+cosx)^(n) dx, snd I_(n)=1/n(sinx+cosx)^(n-1)(sinx-cosx)+(2k)/(n) I_(n-2) then k=

Find dy/dx if y= sinx^cosx .

Find dy/dx if y = (x+sinx )/cosx