`int e^(log_e x)/x dx`

int (1+log_e x)/x dx

If a >0 and a!=1 evaluate the following integrals: inte^x\ a^x\ dx (ii) int2^((log)_e x)\ dx

The value of the integral underset(e^(-1))overset(e^(2))int |(log_(e)x)/(x)|dx is

The value of the integral int_(e^(-1))^(e^2)|((log)_e x)/x| dx is (A) 3/2 (B) 5/2 (C) 3 (D) 5

If a >0 and a!=1 evaluate the following integrals: (i) inte^(x\ (log)_e a)\ dx\ (ii) inte^(a\ (log)_e x)\ dx

Evaluate the integerals. int (e ^(log x))/(x ) dx on (0,oo).

Evaluate int 5^(log _(e)x)dx

int cos (log_e x)dx is equal to

Evaluate : int (e^("log x "))/(x) " dx "

Write a value of int(log)_e x\ dx