If `y=(logx)^x`, then `dy/dx`=?

If x^y=e^(x-y) , then (dy)/(dx) is (a) (1+x)/(1+logx) (b) (1-logx)/(1+logx) (c) not defined (d) (logx)/((1+logx)^2)

If y=acos(logx) , find (dy)/(dx) .

If x+y=sin(x+y) then (dy)/(dx)=

If y=x^(logx)+(logx)^x then find (dy)/(dx)

If y=x^((logx)^log(logx)) then (dy)/(dx)=

If y=(logx)/x , show that (d^2y)/(dx^2)=(2logx-3)/(x^3) .

If y=(logx)/x ,show\ tha t(d^2y)/(dx^2)=(2logx-3)/(x^3)

" If "y=sqrt(logx+sqrt(logx+sqrt(logx+...oo)))," then "(dy)/(dx) is

If y="sin"(logx), then prove that (x^2d^2y)/(dx^2)+x(dy)/(dx)+y=0

If x^y=y^x ,then find (dy)/(dx)