The gravitational force between two point masses `m_1` ​ and `m_2` ​ at separation `r` is given by `F=k(m_1xxm_2)/(r^2)` ​ ​ . The constant k depends on :

The electrostatic force between two charges Q_(1) and Q_(2) at separation r is given by F= (K.Q_(1)Q_(2))/(r^(2)) The constant K

The gravitational force F between two masses m_(1) and m_(2) separeted by a distance r is given by F = (Gm_(1)m_(2))/(r^(2)) Where G is the universal gravitational constant. What are the dimensions of G ?

Write an expression for the gravitational force of attraction between two bodies of masses m_1 and m_2 separated by a distance r .

The gravitational force between a H-atom and another particle of mass m will be given by Newton's law: F=G (M.m)/(r^(2) , where r is in km and

The gravitational force between a H-atom and another particle of mass m will be given by Newton's law: F=G (M.m)/(r^(2) , where r is in km and

Supposing Newton's law of gravitation for gravitation forces F_(1) and F_(2) between two masses m_(1) and m_(2) at positions r_(1) and r_(2) read where M_(0) is a constant of dimension of mass, r_(12) = r_(1) - r_(2) and n is a number. In such a case,

Assertion : The centres of two cubes of masses m_(1) and m_(2) are separated by a distance r. The gravitational force between these two cubes will be (Gm_(1)m_(2))/(r^(2)) Reason : According to Newton's law of gravitation, gravitational force between two point masses m_(1) and m_(2) separated by a distance r is (Gm_(1)m_(2))/(r^(2)) .

If gravitational attraction between two points masses be given by F=G(m_(1)m_(2))/(r^(n)) . Then the period of a satellite in a circular orbit will be proportional to

Gravitational force between two point masses m and M separated by a distance r is F . Now if a point mass 3m is placed next to m , what will be the (a) force on M due to m , (b) total force on M ?