`dy/dx = (x-y-2)/(2x-2y-3)`

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dy/dx = (2x-y)/(x-2y)

dy/dx = (x-y+3)/(2x-2y+5)

dy/dx=(x-y+1)/(2x-2y+3)

(dy)/(dx)=(x+y+1)/(2x+2y+3)

(dy)/(dx)+(x-2y)/(2x-y)=0

The solution of (dy)/(dx)=((x+2y-3)/(2x+y+3))^2, is

9. (dy)/(dx)=(y^(2)-y-2)/(x^(2)+2x-3)

Find dy/dx if y= x-y-2x^2 .

Solve (dy)/(dx)=((x+y)^2)/((x+2)(y-2))