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dy/dx = (2x-y+1)/(2y-x-1)...

`dy/dx = (2x-y+1)/(2y-x-1)`

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dy/dx=(x-y+1)/(2x-2y+3)

dy/dx + (1-2x)/x^2 y=1

Solve the differential equation (dy)/(dx)=(x+2y-1)/(x+2y+1).

If (dy)/dx = (xy)/(x^2 + y^2), y(1) = 1 and y(x) = e then x =

(dy)/(dx)=(x+y+1)/(2x+2y+3)

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If x sqrt ( 1+ y) + y sqrt( 1+x) =0 , prove that (dy)/( dx) = - (1)/( (1+x)^2) .

y^2+x^2(dy)/(dx)=x y(dy)/(dx)

For each of the following differential equations verify that the accompanying functions a solution. (i) x(dy)/(dx)=y => y=a x (ii) x+y(dy)/(dx)=0 => y=+-sqrt(a^2-x^2) (iii) x(dy)/(dx)y+y^2 => y=a/(x+a) (iv) x^3(d^2y)/(dx^2)=1 => y=a x+b+1/(2x) (v) y=((dy)/(dx))^2 => y=1/4(x+-a)^2